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4.9t^2+330t-4356=0
a = 4.9; b = 330; c = -4356;
Δ = b2-4ac
Δ = 3302-4·4.9·(-4356)
Δ = 194277.6
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(330)-\sqrt{194277.6}}{2*4.9}=\frac{-330-\sqrt{194277.6}}{9.8} $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(330)+\sqrt{194277.6}}{2*4.9}=\frac{-330+\sqrt{194277.6}}{9.8} $
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